Development length is the extra length of bar provided beyond the required section in order to ensure the following;
- To develop a safe bond between the bar surface & the concrete so that no failure due to slippage of bar occurs during the ultimate load conditions.
- Also, the extra length of the bar provided as development length is responsible for transferring the stresses developed in any section to the adjoining sections (such as at column beam junction the extra length of bars provided from beam to column).
Calculation of Development length:
As per the Indian Standard – IS 456: 2000, clause 26.2.1 the development length Ld is given the following expression;
Where, Ø = nominal dia of reinforcement bar
σs = Stress in bar at the section considered at design load
τbd = Design bond stress
The above given formula is used to calculate the required development length in mm for any given dia of bar, same formula is used for limit state method as well as working stress method. The only change in calculation in both methods is due to the different value of design bond stress; the values of design bond for Limit State & working stress are as follows;
Design Bond Stress in Limit State Method
|
||||||
Concrete Grade
|
M20
|
M25
|
M30
|
M35
|
M40 & Above
|
|
Design Bond Stress (τbd, N/mm2)
|
1.2
|
1.4
|
1.5
|
1.7
|
1.9
|
For Plain Bars in Tension
|
1.92
|
2.24
|
2.4
|
2.72
|
3.04
|
For deformed bars in tension
|
**Note: For bars in compression 1.25 times the above-given values shall be used.
Design Bond Stress in Working Stress Method
|
||||||||
Concrete Grade
|
M20
|
M25
|
M30
|
M35
|
M40
|
M45
|
M50
|
|
Design Bond Stress (τbd, N/mm2)
|
0.8
|
0.9
|
1.0
|
1.1
|
1.2
|
1.3
|
1.4
|
For Plain Bars in tension
|
1.28
|
1.44
|
1.6
|
1.76
|
1.92
|
2.08
|
2.24
|
For deformed bars in tension
|
Generally, in practice, the development length requirement is expressed as ‘41 times Ø’ or ‘41 Ø’ where 41 is the factor calculated using the above formula & Ø is the dia of the bar.
Example: In the following images, calculation for development length in limit state method (Fig.1), as well as working stress method (Fig.2) for M25 concrete grade & 415 steel grade, are illustrated;Fig-1 (For Limit State Method) |
Fig-2 (For Working Stress Method) |
-----^^^-----
suggestions/comments may be sent to alok.dixit009@gmail.com
simply superb....really nice explanation and example problmes reallyy easy to understand
ReplyDeleteThanks
DeleteVery good to explain the Development length formulas,
ReplyDeleteReally I like it!!!
Thanks
thanks
Deletenanri
ReplyDeleteThis question creat Very big problem for me but now its very easy for this explanation thank you so much
ReplyDeleteThanks
Deletethank you buddy...
ReplyDeleteThanks
DeleteThank u
ReplyDeleteTHANKS BROTHER
DeleteThnks
ReplyDeleteTHANKS
DeleteCan someone please give the table of shear stress in bar in working stress method
ReplyDeleteRefer IS 456
DeleteSORRY BUT I DIDN'T GET YOUR QUESTION EXACTLY, REGARDING SHEAR WHEN THE NOMINAL SHEAR STRESS IN ANY GIVEN BEAM SECTION GOES BEYOND THE MAXIMUM PERMISSIBLE SHEAR STRESS VALUE OF CONCRETE SECTION RELEVANT TO AREA OF CROSS-SECTION OF BEAM & Ast PROVIDED THEN SHEAR REINFORCEMENT IS REQUIRED TO BE PROVIDED. ALSO MINIMUM SHEAR REINFORCEMENT IS MANDATORY FOR PROVISION AS PER IS 456.
DeleteKINDLY REFER ANNEX-B SECTION B-5 OF IS 456: 2000 FOR FURTHER CLARIFICATION REGARDING THE SAME.
u need to correct the value 415 to .87*fy
ReplyDeleteTHE FOS OF 1.15 (CL. 36.4.2.1, IS 456: 2000) AS MENTIONED IN YOUR COMMENT (AS 1/1.15=0.87) IS APPLICABLE FOR DESIGN OF STRUCTURES FOR LIMIT STATE OF COLLAPSE BUT GENERALLY, THE DESIGNS ARE CARRIED OUT WITHIN THE SERVICEABILITY RANGE SO THAT THE STRUCTURE DOES NOT FAIL SUDDENLY BUT INDICATIVE SIGNS WOULD BE EXHIBITED PRIOR TO FAILURE AFTER THE SERVICE RANGE IS CROSSED. THEREFORE FURTHER REDUCTION IN STEEL STRESS IS NOT REQUIRED ALSO IF YOU WILL DECREASE THE STEEL STRESS FURTHER BY USING 0.87 FOS THE VALUE OF DEVELOPMENT LENGTH WILL FURTHER DECREASE WHICH WE WILL HELP YOU IN ACHIEVING THE ECONOMY BUT NOT THE SAFETY. THUS IT IS RECOMMENDED TO USE FE 415/500/550 VALUES ONLY.
DeleteIt's very useful and helpful to me
DeleteThanks for your information
This is the basic formula and explanation mentioned in IS 456, but we don't read it. Rather we prefer to read on internet.
ReplyDeleteTHANKS FOR YOUR COMMENT SIR, AS WE ALL ARE LITTLE LESS ACQUAINTED TO IS CODES AT SOME STAGE IN OUR CAREER & EDUCATION THUS THE SAME HAS BEEN REPRODUCED HERE ALONG WITH THE EXPLANATION FOR THE SAME. REFERENCES OF THE CODES ARE ALSO MENTIONED HERE IN THE POST. THE POINT YOU HAVE RAISED IS QUITE VALID & I ALSO SUPPORT YOU WE ALL SHOULD REFER OUR TEXTS & STANDARDS AS A ROUTINE.
DeleteIt's useful and easily explained
ReplyDeleteThank you
Thanks! Bhavani
Deletesir, how to overcome by the error " the valve of e for member N does not seem to be realistic"
ReplyDeletethank you
The above warning comes in STAAD Pro when you have assigned 'E' (modulus of elasticity) value to a material different from value of steel & then steel code is used for design of the members. In such cases STAAD suggests to check the value of modulus of elasticity for the material.
DeleteSir, But is this formula use full for all the structural member like beams,columns,footings,ext..are the same ?
ReplyDeleteYes this is the same formula for calculation of Ld.
DeleteI think two examples are wrong because putting value is wrong. Please verify it according to IS:456
ReplyDeleteThe values used in the given examples are correct but as you can see in yield stress of steel bars i have not used reduction factor of 0.87 because by upon using the Ld value will be reduced & thus it is not recommended.
DeleteIt is very usefull
ReplyDeleteThanks dear
Deletethnaks man..
ReplyDeleteThanks Sam
Delete
ReplyDeleteThank you very much for the info agan convey and hopefully useful to my friend who read it.
Click Here : farm tractors for sale 260-60 HP TURBO
For designing of bond stress in limit state method, is bond stress value of 1.9 is enough for the grade M40 and above? why so ? since grade of concrete increases, bond stress also increases. Why can't we provide value greater than 1.9 for M40 and above, say for M80? Why IS has certain prescription ?
ReplyDeleteWhat will be the stress for Fe 500/ Fe 550 bar in working stress method ?
ReplyDeleteThankx
ReplyDeleteSir in limit state method
ReplyDeleteDesign bond stress is your wrong.as per IS code
Is M25 mixed concrete 1.4 N/mm2
For limit state method what is the value of bond stress for fe500 steel??
ReplyDeleteIs it 500???
Nice,super THANKYOU SIR
ReplyDeleteCheck for development length along which direction should be considered?
ReplyDeleteHow to find sigma s if not mentioned on drawing
ReplyDeleteHi sir,
ReplyDeleteLength of bolt length required=tension/(pi*dia*bond stress) ....i want derivation ?
please urgent
now a day which method is use in construction limit state or working state which one is suitable and why
ReplyDeletethis length you have calculated 552mm provide both end side or half of both side of the beam section
ReplyDeleteformula sigmab Y = 0.87Fy/4jbd
ReplyDeletewhy there is a factor of 1.25 fro compression compared to that of tension?
ReplyDeletewhy there is a factor of 1.25 for compression compared to that of tension?
ReplyDeleteVery informative post. Development length calculation of steel,You can also know ms steel suppliers in chennai offers a best standard and used for various purposes. The quality steels will be used in a wide range. jsw steel dealers in Chennai also earn the customers trust in the same way like ms steel.
ReplyDeleteClear that you are looking
ReplyDeleteFormula of service of bar
ReplyDeleteIf the concrete grade of the column and beam is different, what concrete grade will follow for the development length of the beam at the column beam junction?
ReplyDeleteAmazing post, thank you for sharing this knowledgeable post, really this is very helpful.Development Length Calculation
ReplyDeleteok
Deletethen where we use this development length formula
ReplyDelete(0.87fyDia/4Tbd)
nice
ReplyDeleteshould we consider a multiplier for bond stress of steel? That is for Fe500 grade steel should we multiply by 0.87 while calculating the development length. Because in most of the material they have used it.
ReplyDeleteVery helpful
ReplyDeleteI am eldin
ReplyDeleteIt was very helpful
What about the lapping length?
ReplyDeleteVery helpful
ReplyDeleteWhat about development length in compression?
ReplyDelete
ReplyDeleteLoad Bearing Structures
standard brick size
Louvered Doors
Batching of Concrete
Floating Slab Vs Monolithic Slab
ReplyDeletecivil engineering interview questions
monolithic slab
Glass Wool Properties
monolithic slab foundation
53 grade cement
Chain Surveying
Grantry Girder
house construction cost calculator excel sheet free download
black cotton soil
wpc
cement test
ppc cement
vacuum concrete
types of aggregates
difference between rigid and flexible pavement
shoring types
types of columns
plastering calculation
pile load test
building planning
what is varnish types of varnish
principles of building planning
tendering process in construction
1001
ReplyDelete1002
1003
1004
1005
1006
1007
1008
1009
1010
1011
1012
1013
1014
1015
1016
1017
1018
ReplyDelete1019
1020
1021
1022
1023
1024
1025
1026
1027
1028
1029
1030
1031
1032
1033
ReplyDelete1034
1035
1036
1037
1038
1039
1040
1041
1042
1043
1044
1045
1046
1047
1048
1049
1050
1051
1052
1053
1054
ReplyDelete1055
1056
1057
1058
1059
1060
1061
1062
1063
1064
1065
1066
thanks for the awesome post Single Roof and Double Roof
ReplyDeleteHi there, yeah this post is genuinely nice and I have learned a lot of things from it concerning blogging. thanks.
ReplyDeleteBathroom Mirrors
Sheet metal forming processes :Sheet metal framing processes are those wherein power is applied to a piece of sheet metal to adjust its calculation as opposed to eliminating any material
ReplyDelete4 CNC Drehmaschine kaufen will make a perfect machien for devlopment
ReplyDeletewhat is carbonmax toe i really don't knwo can you please tell me ??
ReplyDelete