Wednesday, 21 September 2016

Development Length Calculation as per Indian Code

Development length is the extra length of bar provided beyond the required section in order to ensure the following;
  • To develop a safe bond between the bar surface & the concrete so that no failure due to slippage of bar occurs during the ultimate load conditions.
  • Also, the extra length of the bar provided as development length is responsible for transferring the stresses developed in any section to the adjoining sections (such as at column beam junction the extra length of bars provided from beam to column).
Importance: Provision of appropriate development is an important aspect of safe construction practices, proper development length in reinf. bars shall be provided as per the steel grade considered in design otherwise in scenarios where less development length against the required is provided the structures will be prone to encounter  failure due to slippage of joints, bonds, anchors & Laps, in such cases the bars will not yield first but the failure will happen at joints & laps prior to yielding of reinforcement bars.

Calculation of Development length:
As per the Indian Standard – IS 456: 2000, clause 26.2.1 the development length Ld is given the following expression;

 Where,             Ø            = nominal dia of reinforcement bar
 σs               = Stress in bar at the section considered at design load
 τbd           = Design bond stress
The above given formula is used to calculate the required development length in mm for any given dia of bar, same formula is used for limit state method as well as working stress method. The only change in calculation in both methods is due to the different value of design bond stress; the values of design bond for Limit State & working stress are as follows;


Design Bond Stress in Limit State Method
Concrete Grade
M20
M25
M30
M35
M40 & Above

Design Bond Stress (τbd, N/mm2)
1.2
1.4
1.5
1.7
1.9
For Plain Bars in Tension
1.92
2.24
2.4
2.72
3.04
For deformed bars in tension
**Note: For bars in compression 1.25 times the above-given values shall be used.
              

Design Bond Stress in Working Stress Method
Concrete Grade
M20
M25
M30
M35
M40
M45
M50

Design Bond Stress (τbd, N/mm2)
0.8
0.9
1.0
1.1
1.2
1.3
1.4
For Plain Bars in tension
1.28
1.44
1.6
1.76
1.92
2.08
2.24
For deformed bars in tension
**Note: For bars in compression 1.25 times the above given values shall be used.
            

Generally, in practice, the development length requirement is expressed as ‘41 times Ø’ or ‘41 Ø’ where 41 is the factor calculated using the above formula & Ø is the dia of the bar.
Example: In the following images, calculation for development length in limit state method (Fig.1), as well as working stress method (Fig.2) for M25 concrete grade & 415 steel grade, are illustrated;

Fig-1 (For Limit State Method)

Fig-2 (For Working Stress Method)
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suggestions/comments may be sent to alok.dixit009@gmail.com


73 comments:

  1. simply superb....really nice explanation and example problmes reallyy easy to understand

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  2. Very good to explain the Development length formulas,
    Really I like it!!!
    Thanks

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  3. This question creat Very big problem for me but now its very easy for this explanation thank you so much

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  4. Can someone please give the table of shear stress in bar in working stress method

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    Replies
    1. SORRY BUT I DIDN'T GET YOUR QUESTION EXACTLY, REGARDING SHEAR WHEN THE NOMINAL SHEAR STRESS IN ANY GIVEN BEAM SECTION GOES BEYOND THE MAXIMUM PERMISSIBLE SHEAR STRESS VALUE OF CONCRETE SECTION RELEVANT TO AREA OF CROSS-SECTION OF BEAM & Ast PROVIDED THEN SHEAR REINFORCEMENT IS REQUIRED TO BE PROVIDED. ALSO MINIMUM SHEAR REINFORCEMENT IS MANDATORY FOR PROVISION AS PER IS 456.
      KINDLY REFER ANNEX-B SECTION B-5 OF IS 456: 2000 FOR FURTHER CLARIFICATION REGARDING THE SAME.

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  5. u need to correct the value 415 to .87*fy

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    Replies
    1. THE FOS OF 1.15 (CL. 36.4.2.1, IS 456: 2000) AS MENTIONED IN YOUR COMMENT (AS 1/1.15=0.87) IS APPLICABLE FOR DESIGN OF STRUCTURES FOR LIMIT STATE OF COLLAPSE BUT GENERALLY, THE DESIGNS ARE CARRIED OUT WITHIN THE SERVICEABILITY RANGE SO THAT THE STRUCTURE DOES NOT FAIL SUDDENLY BUT INDICATIVE SIGNS WOULD BE EXHIBITED PRIOR TO FAILURE AFTER THE SERVICE RANGE IS CROSSED. THEREFORE FURTHER REDUCTION IN STEEL STRESS IS NOT REQUIRED ALSO IF YOU WILL DECREASE THE STEEL STRESS FURTHER BY USING 0.87 FOS THE VALUE OF DEVELOPMENT LENGTH WILL FURTHER DECREASE WHICH WE WILL HELP YOU IN ACHIEVING THE ECONOMY BUT NOT THE SAFETY. THUS IT IS RECOMMENDED TO USE FE 415/500/550 VALUES ONLY.

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    2. It's very useful and helpful to me
      Thanks for your information

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  6. This is the basic formula and explanation mentioned in IS 456, but we don't read it. Rather we prefer to read on internet.

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    Replies
    1. THANKS FOR YOUR COMMENT SIR, AS WE ALL ARE LITTLE LESS ACQUAINTED TO IS CODES AT SOME STAGE IN OUR CAREER & EDUCATION THUS THE SAME HAS BEEN REPRODUCED HERE ALONG WITH THE EXPLANATION FOR THE SAME. REFERENCES OF THE CODES ARE ALSO MENTIONED HERE IN THE POST. THE POINT YOU HAVE RAISED IS QUITE VALID & I ALSO SUPPORT YOU WE ALL SHOULD REFER OUR TEXTS & STANDARDS AS A ROUTINE.

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  7. It's useful and easily explained

    Thank you

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  8. sir, how to overcome by the error " the valve of e for member N does not seem to be realistic"
    thank you

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    Replies
    1. The above warning comes in STAAD Pro when you have assigned 'E' (modulus of elasticity) value to a material different from value of steel & then steel code is used for design of the members. In such cases STAAD suggests to check the value of modulus of elasticity for the material.

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  9. Sir, But is this formula use full for all the structural member like beams,columns,footings,ext..are the same ?

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    Replies
    1. Yes this is the same formula for calculation of Ld.

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  10. I think two examples are wrong because putting value is wrong. Please verify it according to IS:456

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    Replies
    1. The values used in the given examples are correct but as you can see in yield stress of steel bars i have not used reduction factor of 0.87 because by upon using the Ld value will be reduced & thus it is not recommended.

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  11. Thank you very much for the info agan convey and hopefully useful to my friend who read it.
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  12. For designing of bond stress in limit state method, is bond stress value of 1.9 is enough for the grade M40 and above? why so ? since grade of concrete increases, bond stress also increases. Why can't we provide value greater than 1.9 for M40 and above, say for M80? Why IS has certain prescription ?

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  13. What will be the stress for Fe 500/ Fe 550 bar in working stress method ?

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  14. Sir in limit state method
    Design bond stress is your wrong.as per IS code
    Is M25 mixed concrete 1.4 N/mm2

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  15. For limit state method what is the value of bond stress for fe500 steel??
    Is it 500???

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  16. Check for development length along which direction should be considered?

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  17. How to find sigma s if not mentioned on drawing

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  18. Hi sir,
    Length of bolt length required=tension/(pi*dia*bond stress) ....i want derivation ?

    please urgent

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  19. now a day which method is use in construction limit state or working state which one is suitable and why

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  20. this length you have calculated 552mm provide both end side or half of both side of the beam section

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  21. formula sigmab Y = 0.87Fy/4jbd

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  22. why there is a factor of 1.25 fro compression compared to that of tension?

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  23. why there is a factor of 1.25 for compression compared to that of tension?

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  24. Very informative post. Development length calculation of steel,You can also know ms steel suppliers in chennai offers a best standard and used for various purposes. The quality steels will be used in a wide range. jsw steel dealers in Chennai also earn the customers trust in the same way like ms steel.

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  25. If the concrete grade of the column and beam is different, what concrete grade will follow for the development length of the beam at the column beam junction?

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  26. Amazing post, thank you for sharing this knowledgeable post, really this is very helpful.Development Length Calculation

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  27. then where we use this development length formula

    (0.87fyDia/4Tbd)

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  28. should we consider a multiplier for bond stress of steel? That is for Fe500 grade steel should we multiply by 0.87 while calculating the development length. Because in most of the material they have used it.

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  29. I am eldin
    It was very helpful

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  30. What about the lapping length?

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  31. What about development length in compression?

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